Question

please solve this question

cissy are you here??​

Answer 1

Answer:

Answer 6

1st year

Principal, P=Rs.5000

Time, T=1 year

Rate of interest ,R=6%

∴simple Interest,

5000×10×6

100

=Rs.300

∴Amount=P+SI=Rs.5300

2nd year

Principal = Amount of 1st year=Rs.5300

Rate of interest =8%

Time =1 year

∴ Interest =

5000×1×8

100

=Rs.424

∴ Amount =Rs.(5300+424)=Rs.5724

The interest of 2nd year is the required compound interest. So, C.I=rs.424 and the required amount is Rs.5724

Answer 7

Principal (P) = Rs 20000

Rate (R) = 8% p.a.

Period (T) = 2 years

Hence,

Simple interest (S.I.) = PRT / 100

= Rs (20000 × 8 × 2) / 100

We get,

= Rs 3200

Now,

Amount on compound interest

A = P {1 + (R / 100)}n

= RS 20000 {1 + (8 / 100)}2

On further calculation,

We get,

= Rs 20000 × (27 / 25) × (27 / 25)

= Rs 32 × 729

= Rs 23328

Therefore,

Compound interest = Final amount – (original) Principal

= Rs 23328 – Rs 20000

We get,

= Rs 3328

Hence,

Difference in compound interest – simple interest

= Rs 3328 – Rs 3200

= Rs 128

Step-by-step explanation:

Your dp is so true .

Answer 2

Answer:

Refer above attachments kartik

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