Question

Please solve this question
CLASS 9​

Answer 1

Answer:

hope it helps

Step-by-step explanation:

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Answer 2

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HERE IS UR ANSWER

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$\frac{1}{ \sqrt{3} - \sqrt{2} } - \frac{2}{ \sqrt{5} - \sqrt{3} } + \frac{3}{ \sqrt{5} - \sqrt{2} }$

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$\frac{1}{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } - \frac{2}{ \sqrt{5} - \sqrt{3} } \times \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} + \sqrt{3} } + \frac{3}{ \sqrt{5} - \sqrt{2} } \times \frac{ \sqrt{5} + \sqrt{2} }{ \sqrt{5} + \sqrt{2} }$

Using ,

$(x + y)(x - y) = {x}^{2} - {y}^{2}$

$\frac{ \sqrt{3} + \sqrt{2} }{3 - 2} - \frac{2( \sqrt{5} + \sqrt{3} )}{5 - 3} + \frac{3( \sqrt{5} + \sqrt{2} }{5 - 2}$

$\frac{ \sqrt{3} + \sqrt{2} }{1} - \frac{2 \sqrt{5} + 2 \sqrt{3} }{2} + \frac{3 \sqrt{5} + 3 \sqrt{2} }{3}$

$\sqrt{3} - \frac{2 \sqrt{3} }{2} + \sqrt{2} + \frac{3 \sqrt{2} }{3} - \frac{3 \sqrt{5} }{3} + \frac{2 \sqrt{5} }{2} \\ = \sqrt{3} - \sqrt{3} + \sqrt{2} - \sqrt{2} + \sqrt{5} - \sqrt{5} \\ = 0$