Math, asked by sunilkumar6100pd35li, 10 months ago

please solve this question.....

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Answers

Answered by Anonymous
1

HEYA!!

 \frac{ \sqrt{ \sqrt{5} + 2  } +  \sqrt{ \sqrt{5} - 2 }  }{ \sqrt{ \sqrt{5}  + 1} }

identity uesd :

 {a}^{2} -  {b}^{2} = ( a + b) ( a-b )

 \frac{ (\sqrt{ \sqrt{5} })^{2}  - (2)^{2}  }{ \sqrt{ \sqrt{5} + 1 } }

 \frac{ \sqrt{5} - 4}{ \sqrt{ \sqrt{5}  - 1} }

on rationalisation,

 =  \frac{ \sqrt{5} - 4 \times  \sqrt{ \sqrt{5}   +  1}  }{ \sqrt{ \sqrt{5}  - 1 \times  \sqrt{ \sqrt{5}  + 1} } }

 \frac{ \sqrt{5} - 4 \times  \sqrt{ \sqrt{5} - 4 }  }{ \sqrt{5} - 1 }

you can do the further evaluation now i think

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Answered by RahelSamuel
0

Answer:

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