Question

please solve this question


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Answer 1

The coercivity of the bar magnet is 2600A/m

Given :

length = 0.2 m

Turns = 100

I = 5.2A

1. Formula for magnetic field inside solenoid

2. B=μ₀nI( formula for calculating magnetic field).....1.

also B=μ₀H( also a formula for calculating magnetic field)......2.

comparing above equations we get H=nI

=N/L*I

3.now substitute all values for

=100/0.2*5.2

=100/2*52

=26*100

= 2600 A/m

$\rule{200}{2}$