Question

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Answer 1

Answer:

$\huge{\boxed{\mathcal\pink{\fcolorbox{red}{purple}{Solution:-}}}}$

Coercivity =H= B / μ0

$ni \: = \frac{</em><em>N</em><em>}{l} \times i = \frac{100}{0.2} \times 5.2 \\ \\ = 2600 </em><em>A</em><em>/</em><em>m</em><em>$

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Answer 2

The coercivity of the bar magnet is 2600A/m

Given :

Length = 0.2 m

Turns=100

I=5.2A

1. Formula for magnetic field inside solenoid

2. B=μ₀nI( formula for calculating magnetic field).....1.

also B=μ₀H( also a formula for calculating magnetic field)......2.

comparing above equations we get H=nI

=N/L*I

3.now substitute all values for

=100/0.2*5.2

=100/2*52

=26*100

=2600A/m

$\rule{200}{2}$