Question

please solve this question


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Answer 1

$\rm{Young's \: modulus \: (Y)= \dfrac{Stress}{Strain}} \\ \\ \rm{ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \dfrac{F/A}{\Delta \: l/l}} \\ \\ \rm{Thermal \: Strain = \dfrac{\Delta \: l}{l} = \alpha \Delta T} \\ \\ \rm{ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \dfrac{F}{A(\alpha \Delta T)}}$

Answer 2

Refer to the attached image.