Question

please solve this question

don't spam ​

please explain very very clearly to me
I will really mark you as brainlist ​​​

see the image horizontally
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Answer 1

Answer:

$\huge{\boxed{\rm{\red{x=a²+ab+b²}}}}$

Step-by-step explanation:

Given that:-

a(x-a²)-b(x-b²)=0

=>ax-a³-bx+b³=0

=>(ax-bx)-a³+b³=0

=>x(a-b)-a³+b³=0

=>x(a-b)=a³-b³

=>x=(a³-b³)/(a-b)

=>x=(a-b)(a²+ab+b²)/(a-b)

Cancelling (a-b)

therefore ,x=a²+ab+b²

Answer 2

a(x-a²)-b(x-b²)=0

=>ax-a³-bx+b³=0

=>(ax-bx)-a³+b³=0

=>x(a-b)-a³+b³=0

=>x(a-b)=a³-b³

=>x=(a³-b³)/(a-b)

=>x=(a-b)(a²+ab+b²)/(a-b)

Cancelling (a-b)

therefore ,x=a²+ab+b²