Question

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Answer 1

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Answer 2

Answer:

Step-by-step explanation:

Area of triangle ABC,

By using Heron's Formula, = $\frac{3}{4} \sqrt{11}$ cm²

Area of Triangle DBE and Triangle CFG are equal i.e 0.5 bh

= 4.5 + 4.5 = 9 cm²

Area of triangle BCPQ = bh  = 6.5 cm²

Area of trapezium = sum of parallel sides × $\frac{height}{2}$ = $\frac{3\sqrt[2]{3} }{4}$

Therefore Sum of the areas = 19.48 cm²