Question

please solve this question fast​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\lim_{n \to \infty} a_n \sqrt[n]{x} \sqrt{x} \geq \geq x^{2} \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \pi \neq \sqrt[n]{x} \alpha \sqrt{x} \left \{ {{y=2} \atop {x=2}} \right.$

Step-by-step explanation:

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