please solve this question fast fast
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k i have it if it is divisible by 3
a=n or n+2 or n+4 and b=3
now by euclid's division lemma
a=bq+r where 1 is quotient and 0<_r<1 ,r is remainder
therefore a can be form n or n+1 or n+2
we note that when is divided by n+4 leaves same remainder as it divides n+1
therfore only one out of n, n+1 or n+2 or n+4 is divisible by 3
a=n or n+2 or n+4 and b=3
now by euclid's division lemma
a=bq+r where 1 is quotient and 0<_r<1 ,r is remainder
therefore a can be form n or n+1 or n+2
we note that when is divided by n+4 leaves same remainder as it divides n+1
therfore only one out of n, n+1 or n+2 or n+4 is divisible by 3
mademonikalyani:
or threee
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here is the answer- we know that when an even number is added to an even number it remains even like that odd+even- odd and odd+odd is even so if n is even then only n+1 will only be divided by an odd number and when n is odd then n and n+1 is only dived by odd number and if n is divisible by 3 then n+1 will not be divided by 3 so hence probe
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