Question

please solve this question fast.. it is very urgent....
please....
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Answer 1

Answer:

Hi, here is the complete prove...

Step-by-step explanation:

In △ABC,

AB=AC[Given]

∴∠ACB=∠ABC.....(i)[∵Angle opposite to equal sides are equal]

In △CDF,

∠ACB is an exterior angle.

∴∠ACB>∠DFC[∵Exterior angle property]

⇒∠ABC>∠DFC.....(ii)[From (i)]

Also,

∠DFC=∠AFE[Vertically opposite angles]

⇒∠ABC>∠AFE.....(iii)[From (ii)]

In △BDE,∠DEA is an exterior angle

∴∠DEA>∠ABC

⇒∠DEA>∠AFE[From (iii)]

In △AEF,

∠AEF>∠AFE

∴AF>AE [∵Side opposite to greater angle is greater]