Question

Please Solve This Question Fast.
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Answer 1

$⟹∠AOC + ∠BOC - 180°$

$⟹∠AOC+65°-180°$

$⟹∠AOC =180°-65°$

$⟹∠AOC=115°$

$⟹∠AOC=2∠CDB$

$⟹115°=2∠CDB$

$⟹∠CDB = 115°×2$

$⟹∠CDB = 230°$

Answer 2

Correct answer:-

⟹∠AOC+∠BOC−180°

⟹∠AOC+65°-180°⟹∠AOC+65°−180°

⟹∠AOC =180°-65°⟹∠AOC=180°−65°

⟹∠AOC=115°⟹∠AOC=115°

⟹∠AOC=2∠CDB⟹∠AOC=2∠CDB

⟹115°=2∠CDB⟹115°=2∠CDB

⟹∠CDB = 115°×2⟹∠CDB=115°×2

⟹∠CDB = 230°⟹∠CDB=230°

Final answer:-

option (a) 230°

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