Please solve this question.......
find the image of the point P(-1,2) in the line mirror 2x - 3y +4=0 ?
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Answer:
Explanation:hey mate hope it helps you the answer
(h , k) be image of the point (x1 , y1) to the straight line ax + by + c = 0 is
( h - x1) / a = ( k - y1) /b = -2( ax1 + by1 + c) / a2 + b2 .
Here (x1 , y1) = (1,2) and ax + by + c = 0 is x - 3y + 4 = 0 .
( h - 1) / 1 = ( k - 2) / -3 = -2( 1 - 6 +4) / (1 + 9)
( h - 1) / 1 = ( k - 2) / -3 = -2( -1) / 10
( h - 1) / 1 = ( k - 2) / -3 = 1 / 5
∴ ( h - 1) / 1 = 1 / 5 and ( k - 2) / -3 = 1 / 5
5h - 5 = 1 and 5k - 10 = -3
h = 6 / 5 and 5k = 7
h = 6 / 5 and k = 7/5
the image of the point = ( 6/5 , 7/5)
(h , k) be image of the point (x1 , y1) to the straight line ax + by + c = 0 is
( h - x1) / a = ( k - y1) /b = -2( ax1 + by1 + c) / a2 + b2 .
Here (x1 , y1) = (1,2) and ax + by + c = 0 is x - 3y + 4 = 0 .
( h - 1) / 1 = ( k - 2) / -3 = -2( 1 - 6 +4) / (1 + 9)
( h - 1) / 1 = ( k - 2) / -3 = -2( -1) / 10
( h - 1) / 1 = ( k - 2) / -3 = 1 / 5
∴ ( h - 1) / 1 = 1 / 5 and ( k - 2) / -3 = 1 / 5
5h - 5 = 1 and 5k - 10 = -3
h = 6 / 5 and 5k = 7
h = 6 / 5 and k = 7/5
the image of the point = ( 6/5 , 7/5)
Hope it helps you