Question

❤❤please solve this question ❤❤

❤❤find the value of K if the points A (2, 3), B( 4, k) and C( 6 - 3 ) are collinear. ❤❤

Answer 1

$<b>$
Solution :-

Points :-

A (2, 3), B( 4, k) and C( 6 - 3 )

To prove they are collinear.

Apply staircase Method and equate to zero.

| 2 3 |

| 4 K | × 1/2 = 0

| 6 -3 |

| 2 3 |

$\huge{\bf{\implies}}$= [2k - 3(4) -4(3) - 6(k) + 6(3) -(-3)(2)] ×1/2 = 0

$\huge{\bf{\implies}}$ [ 2k -12 -12-6k+18+6] × 1/2 = 0

$\huge{\bf{\implies}}$ [-4k ] = 0

$\huge{\bf{\implies}}$ K = 0 /-4

$\huge{\bf{\implies}}$ k = 0

$\boxed{\bf{\red{\mathcal{Answer : K= 0}}}}$

Answer 2

Given that A, B and C are collinear

Hence ar(DABC) = 0