Question

please solve this question

find the zero in polynomial x^2+4x+2​

Answer 1

Step-by-step explanation:

x^2+4x+2=0

Here,a=1,b=4,c=2.

x=[-b+( root b^2-4ac)]/2a or [-b-(root b^2-4ac)]

=[-4+( root 12)]/2 or [-4-(root 12)]/2

= -2+ ( root 3 ) or -2-(root 3 ).

Answer 2

Answer:

The question is wrong because the product coefficient of 1st and 3rd term is smaller than the middle term.

It should be x²+4x+12.

x²+6x-2x+12

x(x+6)-2(x+6)

(x-2)(x+6)

Therefore,

x-2=0

x=2 and

x+6=0

x=-6

The zeros are 2 and -6.