Question

Please solve this Question for me.​

Answer 1

Step-by-step explanation:

Given -

Base of an isosceles triangle is 4/3 cm

Perimeter is 62/15 cm

To Find -

What is the length of either of the remaining equal sides ?

As we know that,

perimeter of isocelses triangle = 2a + b

here,

a = two equal sides

b = base

Now,

62/15 = 2a + 4/3

= 62/15 - 4/3 = 2a

= 62-20/15 = 2a

= 42/15 = 2a

= a = 42/30

= a = 7/5 cm

Hence,

The length of either of the remaining equal sides is 7/5 cm.

Verification -

Perimeter = 2a + b

62/15 = 2(7/5) + 4/3

= 62/15 = 14/5 + 4/3

= 62/15 = 42+20/15

= 62/15 = 62/15

LHS = RHS

Hence,

Verified..

Answer 2

QuEsTiOn :-

$The \: base \: of \: an \: isosceles \: triangle \: is \: \frac{4}{3} cm . \: The \: perimeter \\ \: of \: the \: triangle \: is \: 4 \frac{2}{15} cm . \: What \: is \: the \: length \: of \: either \: of \\ \: the \: remaining \: equal \: sides ? </p><p>$

GiVeN :-

• Base of triangle = 4/3 cm

• Perimeter of triangle = 62/15 cm

SoLuTiOn :-

Let the length of equal sides be x cm .

Perimeter = S1 + S2 + S3

Perimeter = x + x + base

$\implies \frac{62}{15} = x + x + \frac{4}{3} \\ \\ \implies \frac{62}{15} = 2x + \frac{4}{3} \\ \\ \implies \frac{62}{15} - \frac{4}{3} = 2x \\ \\ \implies \frac{62 - 20}{15} = 2x \\ \\ \implies \frac{42}{15} = 2x \\ \\ \implies2x = \frac{42}{15} \\ \\ \implies \: x = \frac{42}{15 \times 2} \\ \\ \implies x = \frac{21}{15} \\ \\ \implies \: x = \frac{7}{5}$

Therefore,

${\red{\boxed{\mid{\bold{The \: length \: of \: the \: equal \: sides \: = \frac{7}{5}cm }}}}}$