please solve this question for me
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let \: (x - 2) \: be \: a \:
and \: (y + 1) \: be \: b
therefore \\ the \: equation \: will \: be \: >
= > 12 {a}^{2} + 25ab + 12 {b}^{2}
= > 12 {a}^{2} + 16ab + 9ab \: + 12 {b}^{2}
= > 4a(3a + 4b) + 3b(3a + 4b)
= > (4a + 3b) \: (3a + 4b)
further , you need to substitute the value of a and b in this equation above.
the final answer is:-
= > (4x + 3y - 5) \: (3x + 4y - 2)ation:
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Ashishkumar098:
then your question is wrong
no
it is - only
ok no problem your question your choice , let it be correct
bbyee :)
bye and thanks
mention not
ok
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4
Heya !!
Here's your answer...
____________________________
12 ( x - 2 )² - 25 ( x - 2 ) ( y + 1 ) + 12 ( y + 1 )²
= 12a² + 25ab + 12b²
[ Let , ( x - 2 ) = a , ( y + 1 ) = b ]
= 12a² - 16ab - 9ab + 12b²
= 4a ( 3a - 4b ) - 3b ( 3a - 4b )
= ( 3a - 4b ) ( 4a - 3b )
= { 3 ( x - 2 ) - 4 ( y + 1 ) } { 4 ( x - 2 ) - 3 ( y + 1 ) }
[ • Putting the value of a and b ]
= { 3x - 6 - 4y - 4 } { 4x - 8 - 3y - 3 }
= { 3x - 4y - 10 } { 4x - 3y - 11 }. [ • Required answer ]
__________________________
Thanks !
Here's your answer...
____________________________
12 ( x - 2 )² - 25 ( x - 2 ) ( y + 1 ) + 12 ( y + 1 )²
= 12a² + 25ab + 12b²
[ Let , ( x - 2 ) = a , ( y + 1 ) = b ]
= 12a² - 16ab - 9ab + 12b²
= 4a ( 3a - 4b ) - 3b ( 3a - 4b )
= ( 3a - 4b ) ( 4a - 3b )
= { 3 ( x - 2 ) - 4 ( y + 1 ) } { 4 ( x - 2 ) - 3 ( y + 1 ) }
[ • Putting the value of a and b ]
= { 3x - 6 - 4y - 4 } { 4x - 8 - 3y - 3 }
= { 3x - 4y - 10 } { 4x - 3y - 11 }. [ • Required answer ]
__________________________
Thanks !
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