Math, asked by L12345, 1 year ago

please solve this question friends

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Answered by nitthesh7
0
LHS= (SinA +1/CosA)2 +(CosA+ 1/SinA)2 =((SinACosA +1)/CosA)2 +((SinACosA +1)/SinA)2         
=(SinACosA +1)2/Cos2A +(SinACosA+1)2/Sin2A
     
=(SinACosA +1)2 {1/Cos2A +1/Sin2A}
     
=(SinACosA +1)2 {Sin2A +Cos2A /Sin2 A Cos2 A}
     
=(SinACosA +1)2 {1/Sin2 A Cos2 A) 
     
=( SinA Cos A/SinA Cos A +1/SinA Cos A)2 
     
=(1+CosecA.SecA)2 
    =RHS

    ;hope this ans would help u....



nitthesh7: thanks for brainliest
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