Question

please solve this question from the chapter:motion in a straight line​

Answer 1

${\huge{\bf\red{hy\:mate}}}$

I hope it's useful for u..

${\huge{\bf\green{thanks}}}$

Answer 2

Answer: -1/4x^3

Explanation: Given x^2= 2+t so, x = √2+t

we know, v= dx/dt

so differentiating x to protudge the value of x

dx/dt = d (√2+t)/dt = 1/2(2+t)^-1/2 ( as we can write √ as ^1/2 and dx^n/dx = nx^n-1)

v = 1/2(2+t)^-1/2

differentiating v to get a

dv/dt = d(1/2(2+t)^-1/2)/dt

= -1/4 (2+t)^-3/2 = -1/4(1/√(2+t)^3). (!)

as we have calculated above

x = √2+t

So as per the calculation of eq (!)

a = -1/4x^3

Hope it helped you