Question

please solve this question
give correct solutions only​

Answer 1

Answer:

Solution:

Radius of the first vessel (r1) = 15 cm Height of the first vessel (h1) = 40 cm

Volume of the first vessel = πr1²h1 = 22/7 x 15 x 15 × 40

Volume of the first vessel = 28285.7143

Radius of the second vessel (r2) = 20 cm

Height of the second vessel (h2) = 45 cm

Volume = 22/7 × 20 × 20 × 45 Volume of the second vessel 56571.4286 = cm³

Now, given that

The height of the third vessel which contain milk of the given two vessels (h) = 30 cm. Volume of the third vessel = volume of the first vessel + volume of the second vessel.

: 22/7 × ² × 30 = (28285.7143 + 56571.4286) X X

660r ^ 2 = 84857.1429 * 7

660r ^ 2 = 594000

r² = 594000/660

r ^ 2 = 900

r =√900

r = 30 cm

So, the radius of the third vessel is 30 cm, which will contain the milk which is in the two given vessels.

Answer 2

Answer:

please refer to the pic dear....