Question

please solve this question guys​

Answer 1

Answer:

$\huge \underline \mathfrak \red{Answer}$

Step-by-step explanation:

Since the two cyclists have a 3:43:4 ratio of velocities, we assume they are 3v,4v correspondingly.

Then, the distance of cyclist A from the intersection is given by d1=3vt.

In the same way, the distance of cyclist B from the intersection is given by d2=4vt.

By Pythagorean's theorem we know the distance between the two cyclists is

d= √d² 1 +d² 2−−−−−−√=5vtd=d12+d22=5vt.

Thus, the rate at which two cyclists are separating can be found by taking derivative of dd with respect to time tt. ddt5vt=5vddt5vt=5v

Therefore, the ratio ratio of the rate at which two cyclists are separating with the velocity of A should be 5v3v=535v3v=53. You got it!

I hope it will help you ☺❤☺❤☺❤☺

Answer 2

Answer:

Step-by-step explanation:

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