Physics, asked by Anonymous, 5 months ago

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Answered by sujalnath
3

 \huge\bf\star\fbox\red{Question:-} \huge\bold\pink\bigstar{QUESTION }

QUESTION IS SAYiNG THAT

LINE AB AND CD INTERSECT AT O .

IF <AOC +<BOE=70° AND <BOD =40°FIND <BOE AND REFLEX < COE

{\huge \fbox \pink {A}\fbox \blue {n} \fbox \purple {s} \fbox \green{w} \fbox \red {e} \fbox \orange {r}}

1=GIVEN FROM QUESTION =

<AOC+<BOE=70°

And <BOD=40°

as we know =<AOC+<BOE+<COE=180°

because of linear pair equations ..

as we know <AOC +<BOE=70 and

we don't know the < COE..???????

so

<AOC+<BOE+<COE=180°

70°+<COE=180°

<COE=180-70

The angle of COE=110°

\huge\bold\pink\bigstar{Answer}

2=AND NOW WE HAVE TO FIND THE REFLEX OF <COE

THE TOTAL SUM OF REFLEX ANGLE IS =360°

then simply we have to subtract <COE frm 360°

=360°-110°=== 250°

NOW WE COME TO KNOW THE REFLEX ANGLE OF <COE=250°

\huge\bold\pink\bigstar{Answer}

3=NOW at last we have to find the angle of <BOE

then we know that =

CD=COE+BOE+BOD=180°

<BOE+110°+40°=180°

because linear pair equations

than

<BOE+150°=180°

<BOE=30°

NOW WE COME TO KNOW

THE ANGLE <BOE=30°

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Answered by priyasaini43
3
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