Question

please solve this question I will give 30 points​

Answer 1

Step-by-step explanation:

X=7+$\sqrt{40}$

1/x=$1/7+\sqrt{40}$

By rationalising

1/x=$7-\sqrt{40}$

$\sqrt{x}$=$\sqrt{7+\sqrt{40} }$

1/$\sqrt{x}$=$\sqrt{7-\sqrt{40} }$

By adding them

$\sqrt{7+\sqrt{40} } +\sqrt{7-\sqrt{40} } =x\\Square on both sides,\\7+\sqrt{40} +2\sqrt{7+\sqrt{40} } \sqrt{7-\sqrt{40} }+7-\sqrt{40} =x^2\\\\Use a^2-b^2 formula\\now,\\14+2*49-40=x^2\\x^2=144\\x=12$

Note this x is not question's x

the x is the value of $\sqrt{x} +1/\sqrt{x}$

So ur answer is 12

Hope this helps and i am waiting for my 30 points and pls mark me as brainliest

There might have been a mistake in calculation u can correct it.