Question

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Maths questions

Answer 1

(D) Your answer is in the attachment

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Answer 2

Question-a)

⇒ x + 5 = 7

⇒ x = 7-5

⇒ x = 2

Now, put value of x in second given equation,

⇒ 2x - 3 = ?

⇒ 2(2) - 3 = ?

⇒ 4 - 3 = ?

⇒ 1 = ?

Hence, 2x - 3 = 1.

Question-b)

5x + 5 = - 40

Taking 5 to RHS

⇒ 5x = -40 - 5

⇒ 5x = -45

⇒ x = -45/5

⇒ x = -9

Question-c)

0.5y = 1.5

Take 0.5 to RHS

⇒ y = 1.5/0.5

⇒ y = 3

Question -d)

Put p as 4 and if we get 7 then 4 is p if not then it is not solution.

So,

⇒ 1/2 ( p+3) = 7

⇒ 1/2 (4+3) = 7

⇒ 7/2 = 7

Hence, p as 4 isn't its solution.

Question-e)

Now, take 2 to RHS

⇒ x + 2.4 = 3 * 2

⇒ x + 2.4 = 6

⇒ x = 6 - 2.4

⇒ x = 3.6