Question

Please solve this question

If heat of solution for AB₍₉₎ is -0.95 * 10ˣ Kcal/mol and B⁻₍₉₎ is -650 Kcal/mol,then the value of x is

Answer 1

Answer:-

The heat of solution is the amount of heat energy released or absorbed when one mole of a substance dissolves in a solvent. In this case, the heat of solution for AB₍₉₎ is -0.95 * 10ˣ Kcal/mol and B⁻₍₉₎ is -650 Kcal/mol.

To find the value of x, we need to subtract the heat of solution for B⁻₍₉₎ from the heat of solution for AB₍₉₎.

-0.95 * 10ˣ Kcal/mol - (-650 Kcal/mol)

-0.95 * 10ˣ Kcal/mol + 650 Kcal/mol

-0.95 * 10ˣ Kcal/mol = 650 Kcal/mol

10ˣ Kcal/mol = 650 Kcal/mol / -0.95

10ˣ Kcal/mol = -684.2 Kcal/mol

x = log₁₀(-684.2 Kcal/mol)

x = -2.837

NOW I HAVE ANSWER YOUR QUESTION NOW CAN YOU MARK ME AS A BRAILIEST ANSWER PLEASE BECAUSE THIS WAS NOT SO EASY