Question

Please solve this question....

if you don't know how to solve this than please don't spam here......


Thx ❤​

Answer 1

Answer:

${x}^{3} + {6x}^{2} + 12x + 16 \\ = (x + 4)( {x}^{2} + 2x + 4) \: \: answer$

Mark my brainliest

Answer 2

This question is incomplete and lacks in data.

But if you want to factorize it then

x^3+6x^2+12x+16

=x^3+6x^2+12x+8+8

=x^3+3.x^2.2+3.2^2.x+2^3+8

Now we can use the formula of cube.

=(x+2)^3+2^3

Now we will use another identity here.

=[x+2+2] [(x+2)^2-(x+2)2+2^2]

=[x+4] [x^2+4x+4 -2x-4+4]

=[x+4][x^2+2x+4]

This is the required factorization.

BUT,if they have asked for the roots then

we will have to make it equal to zero.

[x+4][x^2+2x+4]=0

or,x+4=0

or,x=-4

And for the other half,we will be using SHREEDAR ACHARYA’S FORMULA
so,

[x^2+2x+4]=0

or,x={-[2]+-sqroot(2^2–4.1.4)}/2.1

or,x={-2+-sqroot(4–16)}/2

or,x={-2+-sqroot(-12)}/2

or,x=-1+sqroot3i or,,,x=-1-sqroot3i

Hope this helps.