Math, asked by vijendra15, 11 months ago

Please solve this question

If you know the solution then answer if you don't know the solution then don't answer.

Thank you​

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Answers

Answered by kanishka7830
1

 \sqrt{ {x}^{2}  + ax - 1 -  {x}^{2}  - bx + 1}  =  \sqrt{a}  -  \sqrt{b} \\  \sqrt{ax - bx }  =  \sqrt{a } -  \sqrt{b}  \\  \sqrt{a } \times  \sqrt{x} -  \sqrt{b}   \times  \sqrt{x}   =  \sqrt{a}  -  \sqrt{b}  \\  \sqrt{a}  -  \sqrt{b}  =  \sqrt{a}  -  \sqrt{b}

Answered by arvishaali2004
8

Answer:

Step-by-step explanation:

=> Square root of x2+ax-1-x2-bx+1= Root a- root b

=> Root ax- root bx= Root a - root b

=> Root x(root a- root b)= Root a- root b

=> Root x= 1

=> x=1............

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