Math, asked by prashantyadav6140, 7 months ago

Please solve this question immediately please 25 points

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Answered by Anonymous
0

a= 2+root 3, 1/a= 2-root 3

Therefore,( a- 1/a)²

     = [2+ root  3 - ( 2 - root 3)]²

= [2+root 3 - 2+root 3]²

=[root 3]²

= 3

Hope  it  helps you. Please mark me brainliest.

Answered by anandkumar4549
0

Answer: (a - 1/a)^2 = 16

Step-by-step explanation:

If, a = 2 + √3

Then,

1/a = 1/(2 + √3)

On rationalising

1/a = 1/(2 + √3) x (2 - √3)/(2 - √3)

1/a = (2 - √3)/(2 - 3)

So, 1/a = √3 - 2

Now, (a - 1/a) = [ (2+√3) - (√3 - 2) ]

(a - 1/a) = (2+2) = 4

Finally, (a - 1/a)^2 = (4)^2 =16_____(Ans)

I hope it helps you.

Thanks!

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