Question

please solve this question in proper way with good explanation​

Answer 1

Question:-

A body covers 1/3rd of distance with v₁ and remaining with v₂. Find Average velocity.

Answer:-

Let the total distance/displacement travelled by the body be d units.

Given:-

The body covers 1/3rd of distance with v₁

⟹ Distance/displacement covered = d/3

⟹ Velocity = v₁

We know,

Time = Displacement / velocity

So,

⟹ Time taken to travel d/3 units = (d/3) / v₁ = d/3v₁

Also given that,

It covers remaining distance with v₂.

⟹ Remaining distance/displacement = d - d/3 = (3d - d)/3 = 2d/3

⟹ Velocity = v₂

So,

⟹ Time taken to travel 2d/3 units = (2d/3) / v₂ = 2d/3v₂

We know that,

Average velocity = Displacement/Total time.

We have,

• Displacement = d units.
• Time = dv₁/3 + 2dv₂/3 = d/3(1/v₁ + 2/v₂)

Hence,

⟹ Average velocity = d/ (d/3)*(1/v₁ + 2/v₂)

⟹ Average velocity = 1/ (1/3) * (v₂ + 2v₁/v₁v₂)

⟹ Average velocity = 1/ { (2v₁ + v₂)/3v₁v₂ }

⟹ Average velocity = 3v₁v₂/ (2v₁ + v₂) units

Answer 2

Step-by-step explanation:

given :

A body

4G 4:58

covers

3 nel distance with vi and

remaining with V₂.. Find Vasg.

solution :

• average speed = total distance covered / total time taken

• let the total distance =3x

• time taken to cover first one third (x) = t1 = x/v1

• time taken to cover second one third

• =t2= x/v2

• time taken to cover 3rd one third = t3= x/

• v3

• average speed = 3x/(x/v1 +x/v2+x/v3)