Question

please solve this question in rough work class 8​

Answer 1

Answer:

Hey!!

Here is the answer.......

x=-27/19.

Answer 2

Answer:

the value of the equation is $\sf-\frac {27}{19}$

Step-by-step explanation:

$\sf\frac{3x+5}{4x+2}=\frac{3x+4}{4x+7}$

$\sf(3x+5)(4x+2)(4x+2)(3x+4)$

⇒$\sf3x(4x+7)+5(4x+7)=4x(3x+4)+2(3x+4)$

⇒$\sf12x^{2}+21+20x+35=12x^{2}+16x+6x+8$

⇒$\sf12x^{2} -12x^{2}+35-8=(-20x-21x+16x+6x)$

⇒$\sf27=(-41x+22x)$

⇒27 = -41x + 22x

⇒$\sf-\frac {27}{19}= x$