please solve this question it is from compound interest .answer is profit rs 80420........ please
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bhoopendra617:
why u all are not able to solve it
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Answered by
2
Ultimately, your answer stands ₹80420
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![\underline\bold{\huge{ANSWER \: :}} \underline\bold{\huge{ANSWER \: :}}](https://tex.z-dn.net/?f=%5Cunderline%5Cbold%7B%5Chuge%7BANSWER+%5C%3A+%3A%7D%7D)
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Let the present value of land or car be V.
Let the value of land (after uniform growth), and the car (after depreciation) be v.
1⃣ FOR LAND :-
V = Rs. 180000
v = ?
r = 30% (growth)
n = 3 yeas.
Now, v = V ( 1 + r/100)³
=> v = Rs.(180000 × (13/10)³)
=> v = Rs. 395460
2⃣ FOR CAR :-
V = Rs. 320000
r1 = 20% (depreciation)
r2 = 15% (depreciation)
r3 = 15% (depreciation)
Now, v = V (1 - r1/100) (1 - r2/100) (1 - r3/100)
=> v = Rs. (320000×(4/5)×(17/20)×(17/20))
=> v = Rs. 184960
SO, The original cost of land and car
= Rs. (180000+320000)
= Rs. 500000
SIMILARLY, New cost of land and car
= Rs. (395460+184960)
= Rs. 580420
ULTIMATELY, The actual profit
= Rs. (580420 - 500000)
= Rs. 80420 [REQUIRED ANSWER]
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Let the present value of land or car be V.
Let the value of land (after uniform growth), and the car (after depreciation) be v.
1⃣ FOR LAND :-
V = Rs. 180000
v = ?
r = 30% (growth)
n = 3 yeas.
Now, v = V ( 1 + r/100)³
=> v = Rs.(180000 × (13/10)³)
=> v = Rs. 395460
2⃣ FOR CAR :-
V = Rs. 320000
r1 = 20% (depreciation)
r2 = 15% (depreciation)
r3 = 15% (depreciation)
Now, v = V (1 - r1/100) (1 - r2/100) (1 - r3/100)
=> v = Rs. (320000×(4/5)×(17/20)×(17/20))
=> v = Rs. 184960
SO, The original cost of land and car
= Rs. (180000+320000)
= Rs. 500000
SIMILARLY, New cost of land and car
= Rs. (395460+184960)
= Rs. 580420
ULTIMATELY, The actual profit
= Rs. (580420 - 500000)
= Rs. 80420 [REQUIRED ANSWER]
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