please solve this question it is urgent
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total area of Canvas = curved surface of cylinder + curved surface area of cone .
CSA of cylinder= 2πrh
therefore 2*π*24*15
height of conical part= total height of the tent - height of the cylindrical part.
height of the conical part of tent=33-15= 18.
slant height of the cone= √(18)²+(24)². = 30m
therefore CAS of cone = π rl= π *24*30
according to the question
2*π*24*15+π*24*30
= π*24*15(2+2)
= 22/7*24*15*4
= 4525.71
area of Canvas used = 4525.71
and volume of air in tent = 1/3*22/7*24*24*18 + 22/7*24*24*15
= 1/3*22/7*24*24(18+15)
=19913.14
total area of Canvas = curved surface of cylinder + curved surface area of cone .
CSA of cylinder= 2πrh
therefore 2*π*24*15
height of conical part= total height of the tent - height of the cylindrical part.
height of the conical part of tent=33-15= 18.
slant height of the cone= √(18)²+(24)². = 30m
therefore CAS of cone = π rl= π *24*30
according to the question
2*π*24*15+π*24*30
= π*24*15(2+2)
= 22/7*24*15*4
= 4525.71
area of Canvas used = 4525.71
and volume of air in tent = 1/3*22/7*24*24*18 + 22/7*24*24*15
= 1/3*22/7*24*24(18+15)
=19913.14
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