please solve this question..it's our homework ..pls solve it fast...
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Hi!
1. The mesure of A+B+C+D+E+F = 360 .
This is because :-
●A+C+E=180 {All angles of a triangle=180}
●B+D+F=180 {All angles of a triangle=180}
Then, A+B+C+D+E+F = 360 as it is equal to the sum of two triangles.
2. The diagonal of a square equals to 'a' units. The area of the square = a^2 . Then, the area of the 2nd square = 2a^2 as the area of the 2nd square is double that of the first square. Diagonal of a square = √3 a units. Then, diagonal of the 2nd square = √3 2a units.
Thank You
(Hope This Helps)
1. The mesure of A+B+C+D+E+F = 360 .
This is because :-
●A+C+E=180 {All angles of a triangle=180}
●B+D+F=180 {All angles of a triangle=180}
Then, A+B+C+D+E+F = 360 as it is equal to the sum of two triangles.
2. The diagonal of a square equals to 'a' units. The area of the square = a^2 . Then, the area of the 2nd square = 2a^2 as the area of the 2nd square is double that of the first square. Diagonal of a square = √3 a units. Then, diagonal of the 2nd square = √3 2a units.
Thank You
(Hope This Helps)
tanu2222:
thanks a lot
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