please solve this question it's very important.
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Step-by-step explanation:
A right triangle who’s sides are BC =3 and AB +AC +9. We are talking about a 3-4–5 right triangle. With b as the right angle.
This mean that BC (equals 3) is my horizontal side, BA (equals 4) is my vertical side, and AC is the hypotenuse (equals 5).
Cot (c) = 3/4, ==> tan (c) = 4/3, ==> c = 53.13010235 degrees.
sec (c) = 5/3 , ==> cos(c) = 3/5 = c = 53.13010235 degrees.
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Answer:
sinA = 4/5
cos A = 3/5
tanC+secC = sinC/cosC+1/cosC
(sinC+1)/cosC =(3/5+1)/4/5 =2
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