Question

please solve this question it's very important
I will mark it brainliest answer​

Answer 1

$\sf{\large{\underline{\boxed{\pink{\mathsf{♡ ANSWER ♡}}}}}}$

$\green{\large\underline{\underline\mathtt{Given :}}}$ AB =AC & BE is perpendicular to AC.

$\red{\large\underline{\underline\mathtt{Required to prove :}}}$ BC^2 = 2AC.CE

$\sf{\underline{\boxed{\green{\large{\bold{ SOLUTION}}}}}}$⠀⠀⠀⠀

BE^2 = BC^2 +EC^2 ----1

BE^2 =AB^2 +AE ^2 -----2

BC^2+EC^2 =AB^2+AE^2

BC^2 = AC^2 +AE^2-EC^2

=AC^2 +(AE+EC) (AE-EC)

=AC[AC+AE-EC]

HENCE,

${\boxed{BC^2 = 2AC.CE}}$

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