Question

please solve this question it's very important. I will mark it as brainliest please​

Answer 1

Answer:

Hurrayy!

Step-by-step explanation:

Since, ∠ACB is given to be obtuse so the perpendicular AD will meet the BC by extending the line BD to point D.

For better explanation of the solution, see the attached figure of the diagram :

Sine, AD is the perpendicular so ΔABD is right angle triangle.

Now by Pythagoras theorem in ΔABD,

AB² =AD² + BD²

AB² = AD² + (BC+CD)²

AB² = AD² + BC² + CD² + 2×BC×CD

AB² = BC² + AD² + CD² + 2·BC×CD

AB² = BC² + AC² + 2·BC×CD

(since ADC is also right angle triangle using Pythagoras theorem in ΔADC

⇒ AC² = AD² + BD² )

⇒ AB² = BC² + AC² + 2·BC×CD

Hence Proved.

Answer 2

Answer:

Hi your answer is as follows

Step-by-step explanation:

according to Pythagoras theorem,

$AB^{2} = AD^{2} +BD^{2}$

It's also given that ,

BD = BC+CD

As it is $BD^{2}$ it's written as (BC+CD)(BC+CD)

which is ,

$(BC+CD)^{2}$ = $BC^{2} +CD^{2} +2BC.CD$

therefore,

$AB^{2} = BC^{2} +CD^{2} +2BC.CD$

Hence proved

Mark as brainliest if you are satisfied with my answer