Question

Please solve this question. It's very urgent. ​

Answer 1

Answer:

$\frac{dy}{dx} = {e}^{x} - 3 \sin \: x \: + \frac{2}{x}$

Step-by-step explanation:

$y = {e}^{x} + 3 \cos(x) + 2 ln(x)$

differentiating both sides,

$\frac{dy}{dx} = d( {e}^{x} ) + 3 \: d( \cos \: x) + 2 \: d( ln \: x )$

$= {e}^{x} + 3( - \sin \: x \:) + 2( \frac{1}{x} ) \\ \\ = {e}^{x} - 3 \sin \: x \: + \frac{2}{x}$

Hope it helps