Math, asked by kishwerjahan, 9 hours ago

please solve this question.. its a humble request!!

I will mark you as brainliest if you gave the correct answer.. and yes.. i need steps.. not only answer..
pls answer step wise!!! ​

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Answered by sagacioux
6
  • Refer to the attachment!
  • hope it helps :)!
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Answered by Anonymous
7

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\underline{\bf{\underline{Answer-}}}

\implies\large{\bf{\big( \frac{x ^{a} }{ {x}^{b} }\big)  ^ \frac{1}{ab} } \times \: \big(\frac{x ^{b}}{ {x}^{c}}\big) ^{ \frac{1}{bc} }\:  \times \big(\frac{x ^{c}}{ {x}^{a}}\big) ^{ \frac{1}{ca} }  = 1}

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\underline{\bf{\underline{Solution-}}}

\implies\large{\sf{\big( \frac{x ^{a} }{ {x}^{b} }\big)  ^ \frac{1}{ab} } \times \: \big(\frac{x ^{b}}{ {x}^{c}}\big) ^{ \frac{1}{bc} }\:  \times \big(\frac{x ^{c}}{ {x}^{a}}\big) ^{ \frac{1}{ca} }}

\implies\large{\sf{\big( x ^{a - b} \big)  ^ \frac{1}{ab} } \times \: \big( {x}^{b - c} \big) ^{ \frac{1}{bc} }\:  \times \: \big( {x}^{c - a} \big) ^{ \frac{1}{ca}}}

\implies\large{\sf{ x ^{a - b \times \frac{1}{ab}} \times \:  {x}^{b - c  \times \frac{1}{bc} }\:  \times \:x^{c - a \times \frac{1}{ca} }}}

\implies\large{\sf{ x ^{ \frac{a - b}{ab}} \times \:  {x}^{ \frac{b - c }{bc} }\:  \times \:x^{ \frac{c - a}{ca}}}}

\implies\large{\sf{ x ^{ \frac{(a - b)}{ab} +\frac{(b - c) }{bc} +  \frac{(c - a)}{ca}}}}

\implies\large{\sf{ x ^{ \frac{1}{b}-\frac{1}{a}} \times x ^{ \frac{1}{c}-\frac{1}{b}} \times x ^{ \frac{1}{a}-\frac{1}{c}}}}

\implies\large{\sf{ x ^{\frac{1}{b}-\frac{1}{a}+ \frac{1}{c}-\frac{1}{b}+ \frac{1}{a}-\frac{1}{c}}}}

\implies\large{\sf{ x^ {0}}}

\implies\large{\bf{1}}

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\underline{\bf{\underline{Identities\:Applied-}}}

\star\:\:\:{\boxed{\bf{\:\:\frac{x^a}{x^b}=x^{a-b}}}}

\star\:\:\:{\boxed{\:\:\bf{(x^a)^b=x^{ab}}}}

\star\:\:\:{\boxed{\:\:\bf{x^a\times x^b=x^{a+b}}}}

\star\:\:\:{\boxed{\:\:\bf{x^0=1}}}

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