please solve this question motion in a straight line
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Answer:
(2,2) & (0,6)
Explanation:
First of all we need to find the critical value of y, so we will differentiate y with respect to x.
y' = 3x^2 - 6x
3x(x - 2) = 0
so, x = either 2 or 0. These are the critical values.
when x = 2; y = 2
when x = 0; y = 6
Therefore the max and min values are .
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