Question

Please solve this question no. 2​

Answer 1

Answer:

The power and efficiency will be 2000 w and 0.75

Explanation:

Given that,

Mass m = 100 kg

Distance d = 8 m

Time t = 4 sec

Load F= 75 kgf

The effort is 10 N for 1 kg.

So, The effort will be for 100 kg = 1000 N

Load will also be 750 kg.

(a).

The power(P) will be

P= \dfrac{Effort\times Displacement}{time}P=timeEffort×Displacement

P=\dfrac{1000\times8}{4}P=41000×8

P=2000\ wattP=2000 watt

(b).

The efficiency will be

Efficiency =\dfrac{load\times distance}{effort\times distance}Efficiency=effort×distanceload×distance

E=\dfrac{75\times 8}{1000\times 8}E=1000×875×8

E = 0.75E=0.75

Hence, The power and efficiency will be 2000 w and 0.75.

Explanation:

Hope it helps