please solve this question no 6
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Manilachowdary1:
6x^2+9x-8x+12=0 ¥ 3x(2x+3)-4(2x+3) ¥ x=-3/2,4/3
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Firstly take lcm of the upper number
x^2+1/6x-2= 0
x^2 + x -2/6=0
x^2 +x -2=0
x^2 +(2x-x)-2=0
x^2 + 2x - x-2=0
x(x+2)-1(x+2)=0
(x-1)(x+2)=0
x=1,-2
Verification
a+b -b/a
1+(-2) -1/1
-1 -1
Verification
ab c/a
1*-2 -2/1
-2 -2
x^2+1/6x-2= 0
x^2 + x -2/6=0
x^2 +x -2=0
x^2 +(2x-x)-2=0
x^2 + 2x - x-2=0
x(x+2)-1(x+2)=0
(x-1)(x+2)=0
x=1,-2
Verification
a+b -b/a
1+(-2) -1/1
-1 -1
Verification
ab c/a
1*-2 -2/1
-2 -2
This answer is wrong
Answered by
0
6x^2+9x-8x+12
3x(2x+3)-4(2x+3)=0
x=-3/2,4/3
3x(2x+3)-4(2x+3)=0
x=-3/2,4/3
please explain
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