Question

please solve this question....

no wrong answers...

thanku..
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Answer 1

Step-by-step explanation:

sin⁻¹(3/5) - sin⁻¹(8/17) = sin⁻¹[sin(sin⁻¹(3/5) - sin⁻¹(8/17))]

= sin⁻¹[sinsin⁻¹(3/5) × cossin⁻¹(8/17) - cossin⁻¹(3/5) × sinsin⁻¹(8/17)]

=sin⁻¹[3/5 × coscos⁻¹($\frac{\sqrt{17^2-8^2}}{17}$) - coscos⁻¹($\frac{\sqrt{5^2-3^2}}{5}$) ×8/17]

= sin⁻¹[3/5 × 15/17 - 4/5 × 8/17]

=sin⁻¹[9/17 - 32/85]

=sin⁻¹(13/85)

=cos⁻¹($\frac{\sqrt{85^2- 13^2}}{85}$)

=cos⁻¹(84/85)

Answer 2

Step-by-step explanation:

sin⁻¹(3/5) - sin⁻¹(8/17) = sin⁻¹[sin(sin⁻¹(3/5) - sin⁻¹(8/17))]

= sin⁻¹[sinsin⁻¹(3/5) × cossin⁻¹(8/17) - cossin⁻¹(3/5) × sinsin⁻¹(8/17)]

=sin⁻¹[3/5 × coscos⁻¹ - coscos⁻¹

$\frac{ \sqrt{ {17}^{2} - {8}^{2} } }{17}$

-

$\frac{ \sqrt{ {5}^{2} } - {3}^{2} }{5}$

×8/17]

= sin⁻¹[3/5 × 15/17 - 4/5 × 8/17]

=sin⁻¹[9/17 - 32/85]

=sin⁻¹(13/85)

=

${cos}^{ - 1} \frac{ \sqrt{ {85}^{2} - {13}^{2} } }{85}$

=cos⁻¹(84/85)