please solve this question of maths class 12 ... ✌
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Step-by-step explanation:
∫︎cosxdx/(4+sin²x)(1+4(1-cos²x)) =
∫︎cosxdx/(4+sin²x)(1+4sin²x) =
∫︎du/(4+u²)(1+4u²) =
∫︎du/(4+5u²+4u⁴︎) =
∫︎.25du/(1+1.25u²+u⁴︎) =
∫︎.25du/(1–(⁵︎/₈︎)²+(⁵︎/₈︎)²+(⁵︎/₄︎)u²+u⁴︎) =
∫︎.25du/(1-(⁵︎/₈︎)²+(⁵︎/₈︎+u)²) =
∫︎.25du/(³⁹︎/₆︎₄︎+(⁵︎/₈︎+u)²)
∫︎.25dv/(³⁹︎/₆︎₄︎+v²)
∫︎.25(⁶︎⁴︎/₃︎₉︎)dv/(1+v²(⁶︎⁴︎/₃︎₉︎))
∫︎.25(⁶︎⁴︎/₃︎₉︎)dv/(1+(8v/√︎39)²)
∫︎.25(⁸︎/√︎₃︎₉︎)dt/(1+t²)
2arctan(t)/√︎39
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