Please solve this question of Relation and function
class 12th
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Answered by
7
Answer:
-3 (x-(x))^2+2 (x-(x))+a^2
Put X-(X)= L = L greater than equal to L<1
-3L+2L+a^2=0
L= (-2+/- root 4+12a^2)/-6
0 </-(-2+/-root4 +12a^2)/-6<1
0 </-(1+/-root 1+3a^2 )/3 <1
Taking positive sign we get
1+root1+3a^2<3
root1+3a^2 <2
1+3a^2 <4
3a^2<3
a^2<1
Therefore a belongs to (-1,1).
For all integral values of a integral is considered in (-1,0)union (0.1)
Therefore option B is the correct answer for your question..
Hope it helps u mate
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Answered by
4
Answer:
- -3 (x-(x))^2+2 (x-(x))+a^2
- Put X-(X)= L = L greater than equal to L<1
- -3L+2L+a^2=0
- L= (-2+/- root 4+12a^2)/-6
- O</-(-2+/-root4 +12a^2)/-6<1
- 0 </-(1+/-root 1+3a^2 )/3 <1
- Taking positive sign we get
- 1+root1+3a^2<3
- root1+3a^2 <2
- 1+3a^2 <4
- 3a^2<3
- a^2<1
- Therefore a belongs to (-1,1).
- For all integral values of a integral is considered in (-1,0)union (0.1)
- Therefore option B is the correct answer for your question..
Step-by-step explanation:
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