Question

Please solve This Question!

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Answer 1

$\huge \boxed {ANSWER}$

◼$\boxed {FeCl_2}$

Ferrous chloride is formed when ferrous gives its one electron to Chlorine ion.

Since, the valencey of ferrous is +2, two chlorine ions will be required.

▶$[{Cl}^{-1}] \longrightarrow [{Fe}^{+2}]\longleftarrow [{Cl}^{-1}]$

▶$[{Cl}^{-1}] [{Fe}^{+2}][{Cl}^{-1}]$

◼$\boxed {CuCl_2}$

Copper chloride is formed shows it variable valency and becomes divalent loses its one electron to chlorine.Since, valency of copper is +2 ,two chlorine ions will be needed.

▶$[{Cl}^{-1}] \longrightarrow [{Cu}^{+2}]\longleftarrow [{Cl}^{-1}]$

▶$[{Cl}^{-1}] [{Cu}^{+2}][{Cl}^{-1}]$

◼$\boxed { DISTINGUISH }$

⚫$\bold {EXPERIMENT }$

▶ Take two test tubes A and B. Add ferrous chloride in test tube A and copper chloride to test tube B.

▶Add a little amount of sodium hydroxide to both th test tubes.

⚫$\bold {OBSERVATION }$

▶A white precipitate of copper hydroxide is formed in test tube A.

▶A dirty green precipitate of ferrous hydroxide is formed in test tube B.

⚫$\bold {EQUATION }$

IN TEST TUBE A.

▶$FeCl_2 + 2 NaOH \longrightarrow Fe(OH)_2 \downarrow + 2NaCl$

IN TEST TUBE B.

▶$CuCl_2 + 2 NaOH \longrightarrow Cu(OH)_2 \downarrow+ 2NaCl$