please solve this question please.
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Answered by
1
Answer:
here is your answer...
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hope it helps...
mark as brainliest...
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Answered by
0
Answer:
2a-b+c=0
acb is common
abc(4a-b+c)+4ac
abc[2(2a)-b+c]+4ac
abc[2×0]+4ac
abc(0)+4ac
0+4ac
4ac is answer
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