Question

please solve this question ..........please......​

Answer 1

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accelaration of a = a1 and b = a2 and time taken = t1 and t2

distance = ½ a1t1^2 = ½ a2t2^2

so

a1t1^2 = a2t^2 … 1

t2= t1+ t --- 2 (given)

now velocity of a = a1t1 and of b = a2 t2

a1t1 = a2t2 + v(given)

we need to eliminate t1 and t2

or v= a1t1-a2t2

= a2t2^2/t1- a2t2 (sing a1 from 1)

= a2t2(t2 –t1)/t1

= a2 t (t2/t1)

= a2 r (a1/a2)^(1/2) ( from 1)

= t sqrt(a2a1)

Answer 2

Answer:

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