Question

please solve this question please​

Answer 1

GIVEN:

$\rm \bull A \: 40μF \: capacitor \: is \: connected \: to$

$\rm a \: 200V,50Hz \: ac \: supply.$

FIND:

$\rm \bull The \: rms \: value \: of \: current \: in \: the \: circuit = ?$

SOLUTION:

$\rm\to{I}_{rmc} = \frac{{V}_{rmc}}{{X}_{C}}$

$\rm\to{X}_{C} = \frac{1}{wc}$

$\rm\to{X}_{C} = \frac{1}{2 \pi f+ c} \: \: (∵w = 2 \pi f)$

$\rm\to{X}_{C} = \frac{1}{2 \times 3.14 \times 50 \times 40 \times {10}^{ - 6} }$

$\rm\to{X}_{C} = 79.577$

$\rm\to{I}_{rmc} = \frac{200}{79.577} = 2.51A$

Hence, option (c) 2.51A is correct answer.