Math, asked by osvdjsososhshi, 3 months ago

please solve this question PLEASE ​

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Answered by Kanishkasrivastava
1

Answer:

hope this helps please mark me brainliest

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Answered by RvP10
1

Answer:

Proved.

Step-by-step explanation:

\sqrt{\frac{1+sinA}{1-sinA} }\\= \sqrt{\frac{1+sinA}{1-sinA} } \times \sqrt{\frac{1+sinA}{1+sinA} }\\=\sqrt{\frac{(1+sinA)^{2}}{1-(sinA)^{2}} }\\=\frac{(1+sinA)}{(cosA)} \\=1/cosA +sinA/cosA\\=secA + tanA

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