Question

please solve this question PLEASE ​

Answer 1

Answer:

hope this helps please mark me brainliest

Answer 2

Answer:

Proved.

Step-by-step explanation:

$\sqrt{\frac{1+sinA}{1-sinA} }\\= \sqrt{\frac{1+sinA}{1-sinA} } \times \sqrt{\frac{1+sinA}{1+sinA} }\\=\sqrt{\frac{(1+sinA)^{2}}{1-(sinA)^{2}} }\\=\frac{(1+sinA)}{(cosA)} \\=1/cosA +sinA/cosA\\=secA + tanA$