Question

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Answer 1

Answer:

<OAB=x=50°

Explanation:

<AOB=2<ACB. (angle in centre is double of angle at any point of cicle)

<AOB=2×40°=80°

IN ∆OAB

OA=OB. (RADII OF CIRCLE)

<OAB=<OBA

<OAB+<OBA+<AOB=180°

2<OAB+80°=180°

2<OAB=180°-80°

2<OAB=100°

<OAB=100°÷2

<OAB=50°

Answer 2

Answer:

<AOB=2 <ACB [angle in centre is double of angle at any point of circle.

<AOB=2x40°=80°

In ΔOAB

OA=OB[Radii of circle]

<OAB=<OBA

<OAB+<OBA+<AOB=180°

2<OAB+80°=180°

2<OAB=180°-80°

2<OAB=100°

<OAB=100°/2

<OAB=50°

hence proved

Explanation:

hope it's will help u

$by \: eric \: taeyong$